Let $A$ and $B$ be two invertible matrices of order $3 \times 3$. If $\det(ABA^T) = 8$ and $\det(AB^{-1}) = 8$,then $\det(BA^{-1}B^T)$ is equal to

  • A
    $\frac{1}{4}$
  • B
    $1$
  • C
    $\frac{1}{16}$
  • D
    $16$

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