Let $\phi (x) = (x) + {2^{\log _x^3}} - {3^{\log _x^2}}$ then
Let $\phi (x) = (x) + {2^{\log _x^3}} - {3^{\log _x^2}}$ then
- A
$\phi (2) = 2$
- B
$\phi (1) = 0$
- C
$\phi (-1.5) = 0.5$
- D
None
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