In $\odot( O , r),$ the length of minor $\widehat{ ACB }$ is $\frac{1}{6}$ times the circumference of the circle. Then, the measure of the angle subtended at the centre by minor $\widehat{ ACB }$ is .........
In $Fig.$ arcs are drawn by taking vertices $A , B$ and $C$ of an equilateral triangle of side $10 \, cm$. to intersect the sides $BC, CA$ and $AB$ at their respective mid-points $D , E$ and $F$. Find the area of the shaded region (Use $\pi=3.14)$ (in $cm ^{2}$)
Which of the following correctly matches the information given in Part $I$ and Part $II$ ?
Part $I$ | Part $II$ |
$1.$ Formula to find the length of a minor arc | $a.$ $C=2\pi r$ |
$2.$ Formula to find the area of a minor sector | $b.$ $A =\pi r^{2}$ |
$3.$ Formula to find the area of a circle | $c.$ $l=\frac{\pi r \theta}{180}$ |
$4.$ Formula to find the circumference of a circle | $d.$ $A=\frac{\pi r^{2} \theta}{360}$ |
In a circle with radius $14 \,cm ,$ the area of minor sector corresponding to minor $\widehat{ ACB }$ is $77 \,cm ^{2}$. Then, minor $\widehat{ ACB }$ subtends an angle of measure $\ldots \ldots \ldots \ldots$ at the centre.
The maximum area of $\Delta ABC$ inscribed in a semicircle with radius $10 \,cm$ is .......$cm ^{2}$.