Which of the following represents the incorre | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. For carbocations $(Ph_3C^+ > Ph_2CH^+ > PhCH_2^+)$,stability increases with the number of phenyl groups due to resonance stabilization. This

Vedclass · Accepted Answer

$PhCH_2^- < Ph_2CH^- < Ph_3C^-$

Vedclass · Answer

(C) $1$. For carbocations $(Ph_3C^+ > Ph_2CH^+ > PhCH_2^+)$,stability increases with the number of phenyl groups due to resonance stabilization. This order is correct.$2$. For carbon free radicals $(Ph_3C^• > Ph_2CH^• > PhCH_2^•)$,stability increases with the number of phenyl groups due to resonance. This order is correct.$3$. For carbanions $(PhCH_2^- > Ph_2CH^- > Ph_3C^-)$,stability decreases as the number of phenyl groups increases. This is because the negative charge is delocalized over more phenyl rings,but the steric hindrance and the nature of the carbanion stability (which is destabilized by electron-donating groups or resonance that doesn't effectively disperse the charge compared to the inductive effect) make the primary carbanion more stable than the tertiary one in this specific series. Thus,$PhCH_2^- > Ph_2CH^- > Ph_3C^-$ is the correct order of stability.$4$. Therefore,option $C$ $(PhCH_2^- < Ph_2CH^- < Ph_3C^-)$ is the incorrect order.

Which of the following represents the incorrect order of stability?

Similar Questions

Which of the following carbocations is the most stable?

The most stable carbocation among the following is:

Which one of the following species is most stable?

Which of the following carbocations is most stable?

What is the minimum energy required for the homolytic bond fission of the $C-H$ bond in the following molecule?

Vedclass Test Series

Exam Paper Generator

Online Exam Module