Which one of the following species is most st | vedclass

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(B) The stability of a carbocation is increased by electron-donating groups $(EDG)$ and decreased by electron-withdrawing groups $(EWG)$.$1$. The $-NO

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$p-CH_3O-C_6H_4-CH_2^+$

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(B) The stability of a carbocation is increased by electron-donating groups $(EDG)$ and decreased by electron-withdrawing groups $(EWG)$.$1$. The $-NO_2$ group is a strong electron-withdrawing group ($-I$ and $-M$ effect),which destabilizes the carbocation.$2$. The $-OCH_3$ group is an electron-donating group ($+M$ effect),which significantly stabilizes the carbocation by donating electron density through resonance.$3$. The $-Cl$ group is electron-withdrawing ($-I$ effect) but also has a weak $+M$ effect; overall,it is less destabilizing than $-NO_2$ but less stabilizing than $-OCH_3$.$4$. The unsubstituted benzyl carbocation $(C_6H_5-CH_2^+)$ serves as the reference.Therefore,the species with the $-OCH_3$ group is the most stable.

Which one of the following species is most stable?

Similar Questions

Arrange the following free radicals in the correct order of their stability:
$(i)$ $CH_2=\dot{C}H$
$(ii)$ $\dot{C}H_3$
$(iii)$ $CH_3-\dot{C}H-CH_3$
$(iv)$ $(CH_3)_3\dot{C}$

Some pairs of ions are given below. In which pair is the first ion more stable than the second?

$:CCl_2$ is

Based upon an understanding of product stability,predict the product formed when the following dianion reacts with one equivalent of acid $(H^+)$.

The stability of carbanions follows the order:
$I: CH_3CH_2CH_2\bar{C}H_2$
$II: CH_3\bar{C}HCH_2CH_3$
$III: (CH_3)_3\bar{C}$
$IV: CH_3\bar{C}(Ph)CH_2CH_3$

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