In which of the following pairs do the two mo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The bond order $(B.O.)$ is calculated using the formula: $B.O. = \frac{1}{2}[N_b - N_a]$,where $N_b$ is the number of bonding electrons and $N_a$

Vedclass · Accepted Answer

$N_2, O_2^{2+}$

Vedclass · Answer

(A) The bond order $(B.O.)$ is calculated using the formula: $B.O. = \frac{1}{2}[N_b - N_a]$,where $N_b$ is the number of bonding electrons and $N_a$ is the number of antibonding electrons.For $N_2$ ($14$ electrons): $B.O. = \frac{1}{2}[10 - 4] = 3$.For $O_2^{2+}$ ($14$ electrons): $B.O. = \frac{1}{2}[10 - 4] = 3$.Since both $N_2$ and $O_2^{2+}$ have a bond order of $3$,they have identical bond orders.

In which of the following pairs do the two molecules have identical bond order?

Similar Questions

The correct sequence of bond order is

How many bonds (bond order) does $B_2$ have?

Assuming $2s-2p$ mixing is $NOT$ operative,the paramagnetic species among the following is:

During the conversion of peroxide ion $(O_2^{2-})$ to superoxide ion $(O_2^-)$,an electron is removed from which of the following molecular orbitals?

In which of the following transformations,the bond order has increased and the magnetic behaviour has changed?

Vedclass Test Series

Exam Paper Generator

Online Exam Module