Use molecular orbital theory to explain why the $Be_{2}$ molecule does not exist.

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The electronic configuration of Beryllium is $1 s^{2}\, 2 s^{2}$

The molecular orbital electronic configuration for $Be _{2}$ molecule can be written as:

$\sigma _{1s}^2\,\,\sigma _{1s}^{ + 2}\,\,\sigma _{2s}^2\,\,\sigma _{2s}^{ + 2}$

Hence, the bond order for $Be _{2}$ is $\frac{1}{2}\left(N_{b}-N_{a}\right)$

Where

$N_{b}=$ Number of electrons in bonding orbitals

$N_{a}=$ Number of electrons in anti-bonding orbitals

$\therefore $ Bond order of $Be_{2}$ $=\frac{1}{2}(4-4)=0$

A negative or zero bond order means that the molecule is unstable. Hence, $Be _{2}$ molecule does not exist.

Similar Questions

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$A$. have the same energy

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$C$. have same symmetry about the molecular axis

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The pair of species that has the same bond order in the following is

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