Use molecular orbital theory to explain why the $Be_{2}$ molecule does not exist.
The electronic configuration of Beryllium is $1 s^{2}\, 2 s^{2}$
The molecular orbital electronic configuration for $Be _{2}$ molecule can be written as:
$\sigma _{1s}^2\,\,\sigma _{1s}^{ + 2}\,\,\sigma _{2s}^2\,\,\sigma _{2s}^{ + 2}$
Hence, the bond order for $Be _{2}$ is $\frac{1}{2}\left(N_{b}-N_{a}\right)$
Where
$N_{b}=$ Number of electrons in bonding orbitals
$N_{a}=$ Number of electrons in anti-bonding orbitals
$\therefore $ Bond order of $Be_{2}$ $=\frac{1}{2}(4-4)=0$
A negative or zero bond order means that the molecule is unstable. Hence, $Be _{2}$ molecule does not exist.
The linear combination of atomic orbitals to form molecular orbitals takes place only when the combining atomic orbitals
$A$. have the same energy
$B$. have the minimum overlap
$C$. have same symmetry about the molecular axis
$D$. have different symmetry about the molecular axis
Choose the most appropriate from the options given below:
The incorrect statement is :-
The pair of species that has the same bond order in the following is
The bond order is not three for
Give electron configuration, magnetic property bond order and energy diagram for oxygen $\left( {{{\rm{O}}_2}} \right)$ molecule.