In which of the following options,the molecul | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To determine the bond angles,we look at the hybridization and lone pairs of the central atoms: $1$. $H_2O$: $sp^3$ hybridization,$2$ lone pairs,bo

Vedclass · Accepted Answer

$H_2 O < NH_3 < O_3 < SO_2$

Vedclass · Answer

(D) To determine the bond angles,we look at the hybridization and lone pairs of the central atoms: $1$. $H_2O$: $sp^3$ hybridization,$2$ lone pairs,bond angle $\approx 104.5^\circ$. $2$. $NH_3$: $sp^3$ hybridization,$1$ lone pair,bond angle $\approx 107^\circ$. $3$. $O_3$: $sp^2$ hybridization,$1$ lone pair,bond angle $\approx 117^\circ$. $4$. $SO_2$: $sp^2$ hybridization,$1$ lone pair,bond angle $\approx 119^\circ$. Comparing these,the increasing order is $H_2O Thus,the correct option is $D$.

In which of the following options,the molecules are correctly arranged in the increasing order of their bond angles?

Similar Questions

The molecule which has a greater number of lone pairs of electrons than bond pairs of electrons on its central atom is

The molecule having the largest bond angle is

$BeCl_2$ is not isostructural with

What is the geometry of the $H_2O$ molecule?

The number of lone pairs of electrons on the central atoms of $H_{2}O, SnCl_{2}, PCl_{3}$ and $XeF_{2}$ respectively,are

Vedclass Test Series

Exam Paper Generator

Online Exam Module