The number of lone pairs of electrons on the | vedclass

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(A) The number of lone pairs on the central atoms are calculated as follows:$1$. In $H_{2}O$,Oxygen has $6$ valence electrons,$2$ are used in bonding

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$2, 1, 1, 3$

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(A) The number of lone pairs on the central atoms are calculated as follows:$1$. In $H_{2}O$,Oxygen has $6$ valence electrons,$2$ are used in bonding with $H$,leaving $4$ electrons or $2$ lone pairs.$2$. In $SnCl_{2}$,Tin $(Sn)$ has $4$ valence electrons,$2$ are used in bonding with $Cl$,leaving $2$ electrons or $1$ lone pair.$3$. In $PCl_{3}$,Phosphorus $(P)$ has $5$ valence electrons,$3$ are used in bonding with $Cl$,leaving $2$ electrons or $1$ lone pair.$4$. In $XeF_{2}$,Xenon $(Xe)$ has $8$ valence electrons,$2$ are used in bonding with $F$,leaving $6$ electrons or $3$ lone pairs.Thus,the number of lone pairs are $2, 1, 1$ and $3$ respectively.

The number of lone pairs of electrons on the central atoms of $H_{2}O, SnCl_{2}, PCl_{3}$ and $XeF_{2}$ respectively,are

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