BeCl_2 is not isostructural with | vedclass

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(D) $BeCl_2$ has a linear structure due to $sp$ hybridization.$ICl_2^-$ has $sp^3d$ hybridization with $3$ lone pairs on the central atom,resulting in

Vedclass · Accepted Answer

$GeCl_2$

Vedclass · Answer

(D) $BeCl_2$ has a linear structure due to $sp$ hybridization.$ICl_2^-$ has $sp^3d$ hybridization with $3$ lone pairs on the central atom,resulting in a linear geometry.$C_2H_2$ $(HC \equiv CH)$ has $sp$ hybridization and is linear.$XeF_2$ has $sp^3d$ hybridization with $3$ lone pairs on the central atom,resulting in a linear geometry.$GeCl_2$ has $sp^2$ hybridization with $1$ lone pair on the central atom,resulting in a bent (angular) geometry.Therefore,$BeCl_2$ is not isostructural with $GeCl_2$.

List-$I$ (Compound)	List-$II$ (Shape/geometry)
$A$. $NH_3$	$I$. Trigonal Pyramidal
$B$. $BrF_5$	$IV$. Square Pyramidal
$C$. $XeF_4$	$II$. Square Planar
$D$. $SF_6$	$III$. Octahedral

$BeCl_2$ is not isostructural with

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What is the shape of the $ClF_3$ molecule?

Provide the shapes of $H_2O$,$NH_3$,and $SO_2$ including their lone pairs of electrons.

Match List-$I$ with List-$II$.

List-$I$ (Compound) List-$II$ (Shape/geometry)

$A$. $NH_3$ $I$. Trigonal Pyramidal

$B$. $BrF_5$ $IV$. Square Pyramidal

$C$. $XeF_4$ $II$. Square Planar

$D$. $SF_6$ $III$. Octahedral

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