In trapezium $ABCD$,$\overline{AB} \parallel \overline{CD}$ and $\overline{AC} \cap \overline{BD} = \{P\}$. If $PA = 10$,$PC = 15$ and $PD = 12$,then $BD = \ldots$

  • A
    $12.5$
  • B
    $24.5$
  • C
    $20$
  • D
    $25$

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