In the spectrum of light of a luminous heaven | vedclass

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(D) The observed wavelength $\lambda' = 4747 \ \mathring{A}$ is greater than the actual wavelength $\lambda = 4700 \ \mathring{A}$.This shift towards

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$3 	imes 10^6 \ m/s$ moving away from the Earth

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(D) The observed wavelength $\lambda' = 4747 \ \mathring{A}$ is greater than the actual wavelength $\lambda = 4700 \ \mathring{A}$.This shift towards a longer wavelength is known as a redshift,which indicates that the heavenly body is moving away from the Earth.The Doppler shift formula for light is given by $\frac{\Delta \lambda}{\lambda} = \frac{v}{c}$,where $\Delta \lambda = \lambda' - \lambda$.$\Delta \lambda = 4747 \ \mathring{A} - 4700 \ \mathring{A} = 47 \ \mathring{A}$.Substituting the values: $v = \frac{\Delta \lambda \cdot c}{\lambda} = \frac{47 	imes 3 	imes 10^8}{4700}$.$v = \frac{47}{4700} 	imes 3 	imes 10^8 = 0.01 	imes 3 	imes 10^8 = 3 	imes 10^6 \ m/s$.Since it is a redshift,the body is moving away from the Earth.

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