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Question

(B) The Doppler effect for light (redshift) is given by the formula $\frac{\Delta \lambda}{\lambda} = \frac{v}{c}$,where $v$ is the relative velocity

Vedclass · Accepted Answer

$0.4$

Vedclass · Answer

(B) The Doppler effect for light (redshift) is given by the formula $\frac{\Delta \lambda}{\lambda} = \frac{v}{c}$,where $v$ is the relative velocity of the source and $c$ is the speed of light.Given $v = 1.2 	imes 10^6 \, m/s$ and $c = 3 	imes 10^8 \, m/s$.Substituting the values,we get $\frac{\Delta \lambda}{\lambda} = \frac{1.2 	imes 10^6}{3 	imes 10^8}$.$\frac{\Delta \lambda}{\lambda} = 0.4 	imes 10^{-2} = 4 	imes 10^{-3}$.To find the percentage increase,we multiply by $100$: $\frac{\Delta \lambda}{\lambda} 	imes 100 = 4 	imes 10^{-3} 	imes 100 = 0.4 \%$.Therefore,the percentage increase in wavelength is $0.4 \%$.

If the velocity of a galaxy relative to the Earth is $1.2 \times 10^6 \, m/s$,then the percentage increase in the wavelength of light from the galaxy as compared to a similar source on Earth will be ...............$\%$

Similar Questions

$A$ star emitting light of wavelength $5896 \ \mathring{A}$ is moving away from the earth with a speed of $3600 \ km/s$. The wavelength of light observed on earth will be:
($c = 3 \times 10^8 \ m/s$ is the speed of light)

In the context of the Doppler effect in light,the term 'red shift' signifies:

The wavelength of light coming from a star is $3700 \, \mathring{A}$. If the observed wavelength from Earth is $3737 \, \mathring{A}$,what is the velocity of the star? [$c = 3 \times 10^8 \, m/s$]

Assuming that the universe is expanding,if the spectrum of light coming from a star which is moving away from the Earth is tested,then in the wavelength of light:

Write the formula for the Doppler shift for light.

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