In the nuclear reaction { }_{7}^{14} N + X ri | vedclass

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(D) In a nuclear reaction,both the total atomic number $(Z)$ and the total mass number $(A)$ must be conserved on both sides of the equation.Let $X$ b

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${ }_{0}^{1} n$

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(D) In a nuclear reaction,both the total atomic number $(Z)$ and the total mass number $(A)$ must be conserved on both sides of the equation.Let $X$ be represented as ${ }_{Z'}^{A'} X$.The reaction is: ${ }_{7}^{14} N + { }_{Z'}^{A'} X \rightarrow { }_{6}^{14} C + { }_{1}^{1} H$.Conservation of mass number $(A)$: $14 + A' = 14 + 1 \Rightarrow A' = 1$.Conservation of atomic number $(Z)$: $7 + Z' = 6 + 1 \Rightarrow 7 + Z' = 7 \Rightarrow Z' = 0$.$A$ particle with mass number $1$ and atomic number $0$ is a neutron,denoted as ${ }_{0}^{1} n$.

In the nuclear reaction ${ }_{7}^{14} N + X \rightarrow { }_{6}^{14} C + { }_{1}^{1} H$,the $X$ will be

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