A free neutron decays into a proton but a free proton does not decay into neutron. This is because
neutron is an uncharged particle
proton is a charged particle
neutron is a composite particle made of a proton and an electron
neutron has larger rest mass than proton
The radioactive decay of uranium into thorium is expressed by the equation $_{92}^{238}U \to _{90}^{234}Th + X,$ where $'X'$ is
When $_3Li^7$ nuclei are bombarded by protons, and the resultant nuclei are $_4Be^8$, the emitted particles will be
A nuclear decay is possible if the mass of the parent nucleus exceeds the total mass of the decay particles. If $M(A, Z)$ denotes the mass of a single neutral atom of an element with mass number $A$ and atomic number $Z$, then the minimal condition that the $\beta$ decay $X_Z^A \rightarrow Y_{Z+1}^A+\beta^{-}+\bar{v}_e$ will occur is ( $m_e$ denotes the mass of the $\beta$ particle and the neutrino mass $m_v$ can be neglected)
Assertion : Radioactive nuclei emit ${\beta ^ - }$ particles.
Reason : Electrons exist inside the nucleus
In an $\alpha -$ decay, the kinetic energy of $\alpha -$ particle is $48\, MeV$ and $Q$ value of the reaction is $50\, MeV$. The mass number of the mother nucleus is [assume that daughter nucleus is inground state]