A free neutron decays into a proton but a free proton does not decay into neutron. This is because
A free neutron decays into a proton but a free proton does not decay into neutron. This is because
- [JEE MAIN 2023]
- A
neutron is an uncharged particle
- B
proton is a charged particle
- C
neutron is a composite particle made of a proton and an electron
- D
neutron has larger rest mass than proton
Similar Questions
In gamma ray emission from a nucleus
In gamma ray emission from a nucleus
- [AIEEE 2007]
The $\beta$-particles of a radioactive metal originate from
The $\beta$-particles of a radioactive metal originate from
- [KVPY 2015]
In the nuclear reaction $_{85}{X^{297}} \to Y + 4\alpha ,\;Y$ is
In the nuclear reaction $_{85}{X^{297}} \to Y + 4\alpha ,\;Y$ is
Atomic mass number of an element thorium is $232$ and its atomic number is $90$. The end product of this radioactive element is an isotope of lead (atomic mass $208$ and atomic number $82$). The number of alpha and beta particles emitted is
Atomic mass number of an element thorium is $232$ and its atomic number is $90$. The end product of this radioactive element is an isotope of lead (atomic mass $208$ and atomic number $82$). The number of alpha and beta particles emitted is
Statement $-1$ : A nucleus having energy $E _{1}$ decays $\beta^{-}$ emission to daughter nucleus having energy $E _{2}$ but the $\beta^{-}$rays are emitted with a continuous energy spectrum having end point energy $E _{1}- E _{2}$
Statement $-2$ : To conserve energy and momentum in $\beta$ decay at least three particles must take part in the transformation.
Statement $-1$ : A nucleus having energy $E _{1}$ decays $\beta^{-}$ emission to daughter nucleus having energy $E _{2}$ but the $\beta^{-}$rays are emitted with a continuous energy spectrum having end point energy $E _{1}- E _{2}$
Statement $-2$ : To conserve energy and momentum in $\beta$ decay at least three particles must take part in the transformation.
- [AIEEE 2011]