In the given reaction sequence: $HOOC-CH_2-CH_2-COOH$ $\xrightarrow{\Delta} (A)$ $\xrightarrow{CH_3-CH_2-NH_2/\Delta} (B)$. $(B)$ will be:

  • A
    $C_2H_5-NH-CO-CH_2-CH_2-CO-NH-C_2H_5$
  • B
    Option B
  • C
    $HOOC-CH_2-CH_2-COOH$
  • D
    $HOOC-CH_2-CH_2-CONH-C_2H_5$

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Similar Questions

The acid strength of the active methylene group in
$(a)$ $CH_3COCH_2COOC_2H_5$
$(b)$ $CH_3COCH_2COCH_3$
$(c)$ $C_2H_5OOCCH_2COOC_2H_5$
decreases as:

The final product $(III)$ obtained in the reaction sequence is:
$CH_3-CH_2-COOH$ $\xrightarrow{PCl_3} I$ $\xrightarrow{C_6H_6/AlCl_3} II$ $\xrightarrow{NH_2-NH_2/\text{base/heat}} III$

Ethyl ester $\xrightarrow{CH_3MgBr \text{ (excess)}} P$. The product $P$ will be

Match List-$I$ with List-$II$.
List-$I$:
$(a)$ $\text{Benzene} \xrightarrow[\text{CuCl}]{\text{CO, HCl, Anhyd. AlCl}_3} \text{Benzaldehyde}$
$(b)$ $R-CO-CH_3 + NaOX \rightarrow$
$(c)$ $R-CH_2-OH + R'COOH \xrightarrow{\text{Conc. H}_2\text{SO}_4}$
$(d)$ $R-CH_2COOH \xrightarrow[(ii) H_2O]{(i) X_2/\text{Red P}} R-CH(X)COOH$
List-$II$:
$(i)$ $\text{Hell-Volhard-Zelinsky reaction}$
(ii) $\text{Gattermann-Koch reaction}$
(iii) $\text{Haloform reaction}$
(iv) $\text{Esterification}$
Choose the correct answer from the options given below.

Acid hydrolysis of $X$ yields two different organic compounds. Which one of the following is $X$?

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