The acid strength of the active methylene group in
$(a)$ $CH_3COCH_2COOC_2H_5$
$(b)$ $CH_3COCH_2COCH_3$
$(c)$ $C_2H_5OOCCH_2COOC_2H_5$
decreases as:

  • A
    $b > a > c$
  • B
    $c > a > b$
  • C
    $a > c > b$
  • D
    $b > c > a$

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Similar Questions

Which of the following reactions give $RCONH_2$?

Amongst the following,the total number of compounds soluble in aqueous $NaOH$ at room temperature is:
$(I)$ Benzaldehyde
$(II)$ $1$-Naphthol
$(III)$ $4$-(Dimethylamino)phenol
$(IV)$ $4$-Methylphenol
$(V)$ Benzoic acid
$(VI)$ $N,N$-Dimethylcyclohexanamine
$(VII)$ $1$-Naphthoic acid
$(VIII)$ $1,4$-Di-tert-butylbenzene
$(IX)$ $1$-Naphthylmethanol

Match Column-$I$ with Column-$II$ based on the $pK_a$ values of the given carboxylic acids:
Column-$I$Column-$II$
$(A)$ $CF_3COOH$$(i)$ $3.41$
$(B)$ Benzoic acid$(ii)$ $4.76$
$(C)$ $CH_3COOH$$(iii)$ $0.23$
$(D)$ $4$-nitrobenzoic acid$(iv)$ $4.20$

Write the chemical reactions for the following conversions:
$1.$ $1$-Bromopropane to Propan-$1$-ol and Propan-$2$-ol
$2.$ Ethanoic acid to Methanol

Considering the reaction sequence given below,the correct statement$(s)$ is(are):
$A$. $P$ can be reduced to a primary alcohol using $NaBH_4$.
$B$. Treating $P$ with conc. $NH_4OH$ solution followed by acidification gives $Q$.
$C$. Treating $Q$ with a solution of $NaNO_2$ in aq. $HCl$ liberates $N_2$.
$D$. $P$ is more acidic than $CH_3CH_2COOH$.

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