In the given nuclear reaction, the element $X$ is :
${ }_{11}^{22} Na \rightarrow X + e ^{+}+v$
${ }_{10}^{23}\,Ne$
${ }_{10}^{22}\,Ne$
${ }_{12}^{22}\,Mg$
${ }_{11}^{23}\,Na$
Some radioactive nucleus may emit
The nucleus $_{48}^{115}Cd$ after two successive ${\beta ^ - }$ decays will give
The most penetrating radiation out of the following is
In the disintegration series the $_{92}^{238}U\xrightarrow{\alpha }X\xrightarrow{{\beta - }}_Z^AY$ values of $Z$ and $A$ respectively will be
The total number of $\alpha$ and $\beta$ particles emitted in the nuclear reaction ${ }_{92}^{238} \mathrm{U} \rightarrow{ }_{82}^{214} \mathrm{~Pb}$ is