Actinium $231$, ${}^{231}A{c_{89}}$, emit in succession two $\beta  - $particles, four alphas, one $\beta  $ and one alpha plus several $\gamma $ rays. What is the resultant isotope

A certain stable nucleide, after absorbing a neutron, emits $\beta$-particle and the new nucleide splits spontaneously into two $\alpha$-particles. The nucleide is

$_1{H^1}{ + _1}{H^1}{ + _1}{H^2} \to X + {\;_{ + 1}}{e^0} + $energy. The emitted particle is

A radioactive nucleus undergoes a series of decay according to the scheme

$A\xrightarrow{\alpha }{{A}_{1}}\xrightarrow{\beta }{{A}_{2}}\xrightarrow{\alpha }{{A}_{3}}\xrightarrow{\gamma }{{A}_{4}}$

If the mass number and atomic number of $A$ are $180$ and $72$ respectively, then what are these number for $A_4$

A nucleus $_Z{X^A}$ emits $9 \alpha$ - particles and $5 \beta$ particle. The ratio of total protons and neutrons in the final nucleus is

If Alpha, Beta and Gamma rays carry same momentum, which has the longest wavelength