In the given figure,QRST is a square. If the | vedclass

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(C) Let the radius of each circle be $r$.Given that the area of each circle is $\pi r^{2} = 2 \pi$.Dividing both sides by $\pi$,we get $r^{2} = 2$,whi

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$32$

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(C) Let the radius of each circle be $r$.Given that the area of each circle is $\pi r^{2} = 2 \pi$.Dividing both sides by $\pi$,we get $r^{2} = 2$,which implies $r = \sqrt{2}$.The diameter of each circle is $d = 2r = 2\sqrt{2}$.From the figure,the side length of the square $QRST$ is equal to the sum of the diameters of two circles placed side-by-side,so the side length $s = 2d = 2(2\sqrt{2}) = 4\sqrt{2}$.The area of the square $QRST$ is $s^{2} = (4\sqrt{2})^{2} = 16 	imes 2 = 32$ square units.

In the given figure,$QRST$ is a square. If the area of each circle is $2 \pi$,then find the area of square $QRST$?

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