Weekly income of 600 families is tabulated be | vedclass

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(B) First,we construct a cumulative frequency table:						Weekly income (in $Rs.$)			Number of families $(f_i)$			Cumulative frequency $(cf)$							$0

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$1263.15$

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(B) First,we construct a cumulative frequency table:						Weekly income (in $Rs.$)			Number of families $(f_i)$			Cumulative frequency $(cf)$							$0-1000$			$250$			$250$							$1000-2000$			$190$			$440$							$2000-3000$			$100$			$540$							$3000-4000$			$40$			$580$							$4000-5000$			$15$			$595$							$5000-6000$			$5$			$600$			Given $n = 600$,we find $\frac{n}{2} = \frac{600}{2} = 300$.The cumulative frequency just greater than $300$ is $440$,which corresponds to the median class $1000-2000$.Here,lower limit $l = 1000$,frequency $f = 190$,cumulative frequency of the preceding class $cf = 250$,and class size $h = 1000$.Using the median formula:$	ext{Median} = l + \left( \frac{\frac{n}{2} - cf}{f} ight) 	imes h$$= 1000 + \left( \frac{300 - 250}{190} ight) 	imes 1000$$= 1000 + \left( \frac{50}{190} ight) 	imes 1000$$= 1000 + \frac{5000}{19}$$= 1000 + 263.157... \approx 1263.16$Rounding to two decimal places,the median income is $Rs. 1263.15$.

Marks	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$
Number of students	$2$	$4$	$7$	$6$	$1$

Weekly income of $600$ families is tabulated below:

Weekly income Number of families

$0-1000$ $250$

$1000-2000$ $190$

$2000-3000$ $100$

$3000-4000$ $40$

$4000-5000$ $15$

$5000-6000$ $5$

Total $600$

Compute the median income (in $Rs.$).

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Calculate the mean of the scores of $20$ students in a mathematics test:

Marks $10-20$ $20-30$ $30-40$ $40-50$ $50-60$

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Weekly income	Number of families
$0-1000$	$250$
$1000-2000$	$190$
$2000-3000$	$100$
$3000-4000$	$40$
$4000-5000$	$15$
$5000-6000$	$5$
Total	$600$

Weekly income of $600$ families is tabulated below: Weekly income Number of families $0-1000$ $250$ $1000-2000$ $190$ $2000-3000$ $100$ $3000-4000$ $40$ $4000-5000$ $15$ $5000-6000$ $5$ Total $600$ Compute the median income (in $Rs.$).