In the formula bar{x} = A + frac{Sigma f_{i} | vedclass

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(A) The formula provided is for the step-deviation method to calculate the mean of grouped data.In this method,the deviation $d_{i}$ is defined as $d_

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$\frac{x_{i} - A}{c}$

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(A) The formula provided is for the step-deviation method to calculate the mean of grouped data.In this method,the deviation $d_{i}$ is defined as $d_{i} = x_{i} - A$,where $x_{i}$ is the class mark and $A$ is the assumed mean.The variable $u_{i}$ is defined as the ratio of the deviation to the class width $c$,which is given by $u_{i} = \frac{x_{i} - A}{c}$.Therefore,the correct expression for $u_{i}$ is $\frac{x_{i} - A}{c}$.

Income (in $Rs.$)	Number of families
$0-5000$	$8$
$5000-10000$	$26$
$10000-15000$	$41$
$15000-20000$	$16$
$20000-25000$	$3$
$25000-30000$	$3$
$30000-35000$	$2$
$35000-40000$	$1$

In the formula $\bar{x} = A + \frac{\Sigma f_{i} u_{i}}{\Sigma f_{i}} \times c$ for the mean,$u_{i} = \ldots \ldots \ldots$

Similar Questions

The monthly income of $100$ families is given as follows:

Income (in $Rs.$) Number of families

$0-5000$ $8$

$5000-10000$ $26$

$10000-15000$ $41$

$15000-20000$ $16$

$20000-25000$ $3$

$25000-30000$ $3$

$30000-35000$ $2$

$35000-40000$ $1$

Calculate the modal income (in $Rs.$).

In the formula $M = l + \frac{(\frac{n}{2} - cf)}{f} \times h$ for the median,$h = \ldots \ldots \ldots$

For a given frequency distribution,assumed mean $A = 25$,$\Sigma f_{i} d_{i} = 120$ and $\Sigma f_{i} = 140$. Then,the mean $\bar{x} = \dots$

.......... is not a measure of central tendency.

The mean of $15$ observations is $16$. If $2$ is added to each observation and then each result is divided by $3$,the new mean is:

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