In the following state whether $\mathrm{A = B}$ or not :
$A = \{ x:x$ is a multiple of $10\} ;B = \{ 10,15,20,25,30 \ldots \ldots \} $
In the following state whether $\mathrm{A = B}$ or not :
$A = \{ x:x$ is a multiple of $10\} ;B = \{ 10,15,20,25,30 \ldots \ldots \} $
$A = \{ x:x$ is a multiple of $10\} $
$B=\{10,15,20,25,30 \ldots \ldots\}$
It can be seen that $15 \in B$ but $15 \notin A$
$\therefore A \neq B$
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