In the following figure,the flow of liquid through a horizontal pipe is shown. Three tubes $A, B$ and $C$ are connected to the pipe. The radii of the tubes $A, B$ and $C$ at the junction are respectively $2 \ cm, 1 \ cm$ and $2 \ cm$. It can be said that the:

  • A
    Height of the liquid in the tube $A$ is maximum.
  • B
    Height of the liquid in the tubes $A$ and $B$ is the same.
  • C
    Height of the liquid in all the three tubes is the same.
  • D
    Height of the liquid in the tubes $A$ and $C$ is the same.

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In a horizontal tube,the water pressure changes by $1500 \text{ N m}^{-2}$ between points $A$ and $B$ as shown in the figure below. The cross-sectional areas at $A$ and $B$ of the tube are $40 \text{ cm}^2$ and $20 \text{ cm}^2$,respectively. Find the rate of flow of water through the tube.

Water is moving with a speed of $5.0\,m/s$ through a pipe of cross-sectional area $4.0\,cm^2$. The water gradually descends $10\,m$ as the pipe increases in area to $8.0\,cm^2$. If the pressure at the upper level is $1.5 \times 10^5\,Pa$,the pressure at the lower level will be:

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Water is flowing in a streamline manner in a horizontal pipe. If the pressure at a point where the cross-sectional area is $10 \,cm^2$ and velocity is $1 \,m/s$ is $2000 \,Pa$, then the pressure of water at another point where the cross-sectional area is $5 \,cm^2$ is: (in $\,Pa$)

$A$ fully loaded Boeing aircraft has a mass of $3.3 \times 10^{5} \; kg$. Its total wing area is $500 \; m^{2}$. It is in level flight with a speed of $960 \; km/h$.
$(a)$ Estimate the pressure difference between the lower and upper surfaces of the wings.
$(b)$ Estimate the fractional increase in the speed of the air on the upper surface of the wing relative to the lower surface. [The density of air is $\rho = 1.2 \; kg/m^{3}$]

The reading of a pressure meter attached to a closed pipe is $4.5 \times 10^4 \ N/m^2$. On opening the valve,water starts flowing and the reading of the pressure meter falls to $2.0 \times 10^4 \ N/m^2$. The velocity of water is found to be $\sqrt{V} \ m/s$. The value of $V$ is . . . . . .

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