(A) In $\beta^{-}$ decay,the reaction is given by the conservation of mass number and atomic number:${ }_{83}^{210} Bi \longrightarrow { }_{84}^{210}

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(A) In $\beta^{-}$ decay,the reaction is given by the conservation of mass number and atomic number:${ }_{83}^{210} Bi \longrightarrow { }_{84}^{210} X + { }_{-1}^{0} e + \bar{\nu}$Here,the mass number $A = 210$ and the atomic number $Z = 84$ for the daughter nucleus $X$.The number of neutrons $N$ is calculated as $N = A - Z$.$N = 210 - 84 = 126$.

Class 12 Physics Nuclei Properties of Alpha, Beta and Gamma Rays and Decay Process

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In the following equation representing $\beta^{-}$ decay,the number of neutrons in the nucleus $X$ is ${ }_{83}^{210} Bi \longrightarrow X + { }_{-1}^{0} e + \bar{\nu}$

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A
$126$
B
$127$
C
$125$
D
$84$

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In the following equation representing $\beta^{-}$ decay,the number of neutrons in the nucleus $X$ is ${ }_{83}^{210} Bi \longrightarrow X + { }_{-1}^{0} e + \bar{\nu}$

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