When a nucleus with atomic number $Z$ and mass number $A$ undergoes a radioactive decay process :
both $Z$ and $A$ will decrease, if the process is $\alpha$ decay
$Z$ will decrease but $A$ will not change, if the process is $\beta ^+$ decay
$Z$ and $A$ will remain unchanged, if the process is $\gamma$ decay.
all of the above
An atomic nucleus $_{90}T{h^{232}}$ emits several $\alpha$ and $\beta$ radiations and finally reduces to $_{82}P{b^{208}}$. It must have emitted
During a negative beta decay
Given the masses of various atomic particles $m _{ p }=1.0072 u , m _{ n }=1.0087 u$ $m _{ e }=0.000548 u , m _{ v }=0, m _{ d }=2.0141 u$ where $p \equiv$ proton, $n \equiv$ neutron, $e \equiv$ electron, $\overline{ v } \equiv$ antineutrino and $d \equiv$ deuteron. Which of the following process is allowed by momentum and energy conservation $?$
A nucleus of atomic mass $A$ and atomic number $Z$ emits ${M_1}$ particles. The atomic mass and atomic number of the resulting nucleus are
Before the neutrino hypothesis, the beta decay process was thought to be the transition, $n \to p + {e^ - }$ If this was true, show that if the neutron was at rest, the proton and electron would emerge with fixed energies and calculate them. Experimentally, the electron energy was found to have a large range.