In the following common emitter circuit, if b | vedclass

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(B) Given that, $V_{CE}=7 \, V$, $\beta=100$, $R_C=2 \, k\Omega = 2000 \, \Omega$, and $V_{CC}=15 \, V$.We know that the current gain in a common emit

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$0.04$

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(B) Given that, $V_{CE}=7 \, V$, $\beta=100$, $R_C=2 \, k\Omega = 2000 \, \Omega$, and $V_{CC}=15 \, V$.We know that the current gain in a common emitter circuit is given by:$\beta = \frac{I_C}{I_B} \dots (i)$Applying Kirchhoff's Voltage Law $(KVL)$ in the output loop (collector-emitter loop):$V_{CC} - I_C R_C - V_{CE} = 0$Substituting the given values:$15 - I_C(2000) - 7 = 0$$8 = I_C(2000)$$I_C = \frac{8}{2000} \, A = 4 	imes 10^{-3} \, A = 4 \, mA \dots (ii)$Now, substituting the value of $I_C$ from equation $(ii)$ into equation $(i)$:$100 = \frac{4 \, mA}{I_B}$$I_B = \frac{4}{100} \, mA = 0.04 \, mA$.

In the following common emitter circuit, if $\beta=100$, $V_{CE}=7 \, V$, $V_{BE}$ is negligible, and $R_C=2 \, k\Omega$, then $I_B=$ (in $\, mA$)?

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