$A$ $N-P-N$ transistor is connected in common emitter configuration (see figure) in which the collector voltage drop across the load resistance $(800 \; \Omega)$ connected to the collector circuit is $0.8 \; V$. The collector current is .............. $mA$.

$10^{10}$ electrons enter the emitter of a junction transistor in a time of $0.4 \mu s$. If $5 \%$ of the electrons are lost in the base, then the collector current is (in $\text{ mA}$)

For a common base circuit,if $\frac{I_C}{I_E} = 0.98$,then the current gain for a common emitter circuit will be:

$A$ transistor having a $\beta$ equal to $80$ has a change in base current of $250 \mu A$. What is the change in collector current?

The typical output characteristics curve for a transistor working in the common-emitter configuration is shown in the figure. The estimated current gain from the figure is

In the figure,given that $V_{BB}$ supply can vary from $0$ to $5.0 \,V$,$V_{CC} = 5\,V$,$\beta_{dc} = 200$,$R_B = 100\,k\Omega$,$R_C = 1\,k\Omega$ and $V_{BE} = 1.0\,V$. The minimum base current and the input voltage at which the transistor will go to saturation,will be respectively: