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(B) transistor consists of two $pn$ junctions. $1$. No conduction between $P$ and $Q$ implies that $P$ and $Q$ are the collector and emitter terminals

Vedclass · Accepted Answer

It is an $npn$ transistor with $R$ as base

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(B) transistor consists of two $pn$ junctions. $1$. No conduction between $P$ and $Q$ implies that $P$ and $Q$ are the collector and emitter terminals (or vice versa),as there is no direct $pn$ junction between them. $2$. When the negative terminal of the multimeter is connected to $R$ and the positive terminal is connected to $P$ or $Q$,conduction (resistance) is observed. $3$. In a multimeter,the common (negative) terminal is connected to the internal battery's negative pole,and the positive terminal is connected to the positive pole. $4$. Conduction occurs when the $pn$ junction is forward-biased. $5$. Since the negative terminal is at $R$ and the positive terminal is at $P$ or $Q$,$R$ must be the $p$-type material (base) and $P, Q$ must be $n$-type materials. $6$. This configuration corresponds to an $npn$ transistor where $R$ is the base.

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