In the figure shown, after the switch $‘S’$ is turned from position $‘A’$ to position $‘B’$, the energy dissipated in the circuit in terms of capacitance $‘C’$ and total charge $‘Q’$ is

820-1106

  • [JEE MAIN 2019]
  • A

    $\frac{1}{8}\frac{{{Q^2}}}{C}$

  • B

    $\frac{3}{8}\frac{{{Q^2}}}{C}$

  • C

    $\frac{5}{8}\frac{{{Q^2}}}{C}$

  • D

    $\frac{3}{4}\frac{{{Q^2}}}{C}$

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