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(D) The correct option is $D$.$1$. The capacitance of a parallel plate capacitor is given by $C = \frac{\varepsilon_0 A}{d}$. When the distance $d$ be

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the electrostatic energy stored in the capacitor decreases

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(D) The correct option is $D$.$1$. The capacitance of a parallel plate capacitor is given by $C = \frac{\varepsilon_0 A}{d}$. When the distance $d$ between the plates is increased,the capacitance $C$ decreases.$2$. Since the battery remains connected,the potential difference $V$ across the plates remains constant.$3$. The charge on the capacitor is given by $Q = CV$. Since $C$ decreases and $V$ is constant,the charge $Q$ decreases.$4$. The electrostatic energy stored in the capacitor is given by $U = \frac{1}{2}CV^2$. Since $C$ decreases and $V$ is constant,the stored energy $U$ decreases.

$A$ parallel plate capacitor is charged fully by using a battery. Then,without disconnecting the battery,the plates are moved further apart. Then,

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