In the expansion of {left( x - frac{1}{x} rig | vedclass

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(A) The general term in the expansion of ${\left( x - \frac{1}{x} \right)^6}$ is given by $T_{r+1} = {^6C_r} \cdot x^{6-r} \cdot \left( -\frac{1}{x} \

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$-20$

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(A) The general term in the expansion of ${\left( x - \frac{1}{x} \right)^6}$ is given by $T_{r+1} = {^6C_r} \cdot x^{6-r} \cdot \left( -\frac{1}{x} \right)^r$.Simplifying this,we get $T_{r+1} = {^6C_r} \cdot (-1)^r \cdot x^{6-r} \cdot x^{-r} = {^6C_r} \cdot (-1)^r \cdot x^{6-2r}$.For the term to be independent of $x$ (the constant term),the exponent of $x$ must be $0$,so $6 - 2r = 0$,which implies $r = 3$.Substituting $r = 3$ into the expression,the constant term is ${^6C_3} \cdot (-1)^3 = 20 \cdot (-1) = -20$.

In the expansion of ${\left( x - \frac{1}{x} \right)^6}$,the constant term is

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