In an EM wave,the amplitude of the magnetic f | vedclass

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Question

(D) In an electromagnetic wave,the relationship between the amplitude of the electric field $E_0$ and the amplitude of the magnetic field $B_0$ is giv

Vedclass · Accepted Answer

$H_0 = E_0 \sqrt{\frac{\varepsilon_0}{\mu_0}}$

Vedclass · Answer

(D) In an electromagnetic wave,the relationship between the amplitude of the electric field $E_0$ and the amplitude of the magnetic field $B_0$ is given by $E_0 = c B_0$,where $c$ is the speed of light in vacuum.Since $B_0 = \mu_0 H_0$,we can substitute this into the equation: $E_0 = c \mu_0 H_0$.We know that $c = \frac{1}{\sqrt{\mu_0 \varepsilon_0}}$.Substituting $c$ into the equation: $E_0 = \frac{1}{\sqrt{\mu_0 \varepsilon_0}} \cdot \mu_0 H_0 = \sqrt{\frac{\mu_0}{\varepsilon_0}} H_0$.Rearranging for $H_0$,we get: $H_0 = E_0 \sqrt{\frac{\varepsilon_0}{\mu_0}}$.

In an $EM$ wave,the amplitude of the magnetic field $H_0$ and the amplitude of the electric field $E_0$ at any place are related as:

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