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(C) Given: Amplitude of magnetic field $B_m = 510 \, nT = 510 	imes 10^{-9} \, T$.Speed of light in vacuum $c = 3 	imes 10^8 \, m/s$.The relationshi

Vedclass · Accepted Answer

$1.53 	imes 10^2 \, V/m$

Vedclass · Answer

(C) Given: Amplitude of magnetic field $B_m = 510 \, nT = 510 	imes 10^{-9} \, T$.Speed of light in vacuum $c = 3 	imes 10^8 \, m/s$.The relationship between the amplitudes of the electric field $(E_m)$ and magnetic field $(B_m)$ in an electromagnetic wave is given by $E_m = c B_m$.Substituting the values:$E_m = (3 	imes 10^8 \, m/s) 	imes (510 	imes 10^{-9} \, T)$$E_m = 1530 	imes 10^{-1} \, V/m$$E_m = 153 \, V/m = 1.53 	imes 10^2 \, V/m$.Thus,the correct option is $C$.

If the amplitude of the magnetic field component of an electromagnetic wave in vacuum is $B_m = 510 \, nT$,then the amplitude of the electric field component of the wave is ......

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