In polythionic acid,H_{2}S_{x}O_{6} (x=3 to 5 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The structure of polythionic acid $H_{2}S_{x}O_{6}$ consists of two terminal sulfur atoms bonded to three oxygen atoms each (one double-bonded,one

Vedclass · Accepted Answer

$0$ and $+5$ only

Vedclass · Answer

(D) The structure of polythionic acid $H_{2}S_{x}O_{6}$ consists of two terminal sulfur atoms bonded to three oxygen atoms each (one double-bonded,one double-bonded,and one hydroxyl group),and a chain of $(x-2)$ sulfur atoms in the middle.In the terminal sulfur atoms,the oxidation state is $+5$ due to bonding with three oxygen atoms and one sulfur atom.The central sulfur atoms are bonded only to other sulfur atoms,so their oxidation state is $0$.Therefore,the oxidation states present are $0$ and $+5$.

In polythionic acid,$H_{2}S_{x}O_{6}$ ($x=3$ to $5$),the oxidation state$(s)$ of sulfur is/are:

Similar Questions

The oxidation number of $C$ atom in $CH_{2}Cl_{2}$ and $CCl_{4}$ are respectively:

$A$ compound contains atoms of three elements $A$,$B$ and $C$. If the oxidation number of $A$ is $+2$,$B$ is $+5$ and that of $C$ is $-2$,the possible formula of the compound is:

The oxidation number of chlorine in $HOCl$ is:

The oxidation number of $N$ in $NH_3$ is:

In which of the following compounds is the oxidation number of carbon maximum?

Vedclass Test Series

Exam Paper Generator

Online Exam Module