In which of the following compounds is the ox | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To find the oxidation number of $C$,let it be $x$:$1.$ For $HCHO$: $x + 1(+1) + 1(-2) + 1(+1) = 0 \implies x + 2 - 2 = 0 \implies x = 0$.$2.$ For

Vedclass · Accepted Answer

$CHCl_3$

Vedclass · Answer

(B) To find the oxidation number of $C$,let it be $x$:$1.$ For $HCHO$: $x + 1(+1) + 1(-2) + 1(+1) = 0 \implies x + 2 - 2 = 0 \implies x = 0$.$2.$ For $CHCl_3$: $x + 1(+1) + 3(-1) = 0 \implies x + 1 - 3 = 0 \implies x = +2$.$3.$ For $CH_3OH$: $x + 3(+1) + 1(-2) + 1(+1) = 0 \implies x + 3 - 2 + 1 = 0 \implies x = -2$.$4.$ For $C_{12}H_{22}O_{11}$: $12x + 22(+1) + 11(-2) = 0 \implies 12x + 22 - 22 = 0 \implies 12x = 0 \implies x = 0$.Comparing the values,the maximum oxidation number is $+2$ in $CHCl_3$.

In which of the following compounds is the oxidation number of carbon maximum?

Similar Questions

What are the respective oxidation states of sulphur atoms numbered $1$ to $4$ in the tetrathionate ion $(S_4O_6^{2-})$ shown below?

When $SO_2$ is passed through an acidic solution of potassium dichromate,chromium sulphate is formed. What is the change in the oxidation state of chromium?

In the reaction,$MnO_{4(aq)}^{-} + Br_{(aq)}^{-} \rightarrow MnO_{2(s)} + BrO_{3(aq)}^{-}$,the correct change in oxidation number of the species involved is

An acidified solution of sodium thiosulfate is unstable because in thiosulfate,the two sulfur atoms are in:

What are the oxidation numbers of the underlined elements in each of the following and how do you rationalise your results?
$(a)$ $K\underline {I_3}$
$(b)$ $H_2\underline {S_4}O_6$
$(c)$ $\underline {Fe_3}O_4$
$(d)$ $\underline {C}H_3\underline {C}H_2OH$
$(e)$ $\underline {C}H_3\underline {C}OOH$

Vedclass Test Series

Exam Paper Generator

Online Exam Module