(C) Let the oxidation number of chlorine be $x$. In $HOCl$,the oxidation number of hydrogen $(H)$ is $+1$ and oxygen $(O)$ is $-2$. The sum of oxidati

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(C) Let the oxidation number of chlorine be $x$. In $HOCl$,the oxidation number of hydrogen $(H)$ is $+1$ and oxygen $(O)$ is $-2$. The sum of oxidation numbers in a neutral molecule is $0$. So,$(+1) + x + (-2) = 0$. $x - 1 = 0$. $x = +1$. Therefore,the oxidation number of chlorine in $HOCl$ is $+1$.