In the nitration of benzene,concentrated HNO_ | vedclass

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Question

(A) In the nitration of benzene,the reaction between concentrated $HNO_3$ and concentrated $H_2SO_4$ occurs as follows:$HNO_3 + H_2SO_4 \rightleftharp

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Bronsted base

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(A) In the nitration of benzene,the reaction between concentrated $HNO_3$ and concentrated $H_2SO_4$ occurs as follows:$HNO_3 + H_2SO_4 \rightleftharpoons H_2NO_3^+ + HSO_4^-$$H_2NO_3^+ \rightleftharpoons H_2O + NO_2^+$Here,$HNO_3$ accepts a proton $(H^+)$ from $H_2SO_4$ to form $H_2NO_3^+$. According to the Bronsted-Lowry theory,a substance that accepts a proton acts as a Bronsted base.

In the nitration of benzene,concentrated $HNO_3$ acts as a:

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