A C_8H_{10} hydrocarbon is nitrated by HNO_3 | vedclass

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Question

(B) The hydrocarbon $C_8H_{10}$ can be ethylbenzene or one of the three xylenes (ortho,meta,or para).$1$. Ethylbenzene: Nitration occurs at ortho,meta

Vedclass · Accepted Answer

ortho-xylene

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(B) The hydrocarbon $C_8H_{10}$ can be ethylbenzene or one of the three xylenes (ortho,meta,or para).$1$. Ethylbenzene: Nitration occurs at ortho,meta,and para positions,yielding three isomers.$2$. Ortho-xylene ($1,2$-dimethylbenzene): Nitration can occur at the $3$-position or $4$-position,yielding two isomers.$3$. Meta-xylene ($1,3$-dimethylbenzene): Nitration can occur at the $2, 4,$ or $5$-position,yielding three isomers.$4$. Para-xylene ($1,4$-dimethylbenzene): Nitration occurs at only one equivalent position,yielding only one isomer.Since the question states that exactly two isomers are obtained,the hydrocarbon must be ortho-xylene.

$I. -OH$	$II. -CN$
$III. -CO_2H$	$IV. -OCH_3$
$V. -NHCOCH_3$	$VI. -CHO$

$A$ $C_8H_{10}$ hydrocarbon is nitrated by $HNO_3$ and sulphuric acid. Two,and only two,$C_8H_9NO_2$ isomers are obtained. Which of the following fits this evidence?

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