In how many ways can $6$ persons be selected from $4$ officers and $8$ constables,if at least one officer is to be included?

  • A
    $224$
  • B
    $672$
  • C
    $896$
  • D
    None of these

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$X, Y, Z$ are sets of all positive divisors of $10^{60}, 20^{50}$ and $30^{40}$ respectively. Find $n(X \cup Y \cup Z)$.

$^{20}C_1 + 3 ^{20}C_2 + 3 ^{20}C_3 + ^{20}C_4$ is equal to-

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$^nC_r \div ^nC_{r-1} = $

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