To fill 12 vacancies,there are 25 candidates, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Total candidates = $25$. Scheduled caste candidates = $5$. Other candidates = $25 - 5 = 20$.Total vacancies = $12$. Reserved vacancies for schedul

Vedclass · Accepted Answer

$^5C_3 	imes ^{22}C_9$

Vedclass · Answer

(A) Total candidates = $25$. Scheduled caste candidates = $5$. Other candidates = $25 - 5 = 20$.Total vacancies = $12$. Reserved vacancies for scheduled caste = $3$. Open vacancies = $12 - 3 = 9$.Step $1$: Selection for $3$ reserved vacancies from $5$ scheduled caste candidates can be done in $^5C_3$ ways.Step $2$: After filling $3$ reserved seats,the remaining candidates are $25 - 3 = 22$ (since $2$ scheduled caste candidates were not selected for reserved seats,they are now eligible for the open seats along with the $20$ other candidates).Step $3$: The remaining $9$ vacancies are open to all remaining $22$ candidates. This can be done in $^{22}C_9$ ways.Total number of ways = $^5C_3 	imes ^{22}C_9$.

To fill $12$ vacancies,there are $25$ candidates,of which $5$ are from the scheduled caste. If $3$ of the vacancies are reserved for scheduled caste candidates while the rest are open to all,then the number of ways in which the selection can be made is:

Similar Questions

The sum of the divisors of $2^5 \cdot 3^4 \cdot 5^2$ is

In how many different ways can the letters of the word '$PRAISE$' be arranged?

In how many ways can the letters of the word '$UNIVERSAL$' be arranged when $E, R, S$ are always together?

$A$ student is to answer $10$ out of $13$ questions in an examination such that he must choose at least $4$ from the first $5$ questions. The number of choices available to him is

From $8$ men and $6$ women,a group of seven persons is to be formed. In how many ways can the group be formed such that the group includes at least two ladies?

Vedclass Test Series

Exam Paper Generator

Online Exam Module