In the figure,a +Q charge is located at one o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) According to Gauss's Law,the total electric flux through a closed surface is $\frac{1}{\epsilon_0}$ times the total charge enclosed by the surface

Vedclass · Accepted Answer

$\frac{Q}{8\epsilon_0}$

Vedclass · Answer

(D) According to Gauss's Law,the total electric flux through a closed surface is $\frac{1}{\epsilon_0}$ times the total charge enclosed by the surface.When a charge $+Q$ is placed at a corner of a cube,it is shared by $8$ identical cubes to completely enclose the charge in a symmetric manner.Therefore,the flux through one cube is $\frac{1}{8}$ of the total flux $\frac{Q}{\epsilon_0}$ that would pass through a Gaussian surface enclosing the charge completely.Thus,the electric flux through the cube is $\Phi = \frac{Q}{8\epsilon_0}$.

In the figure,a $+Q$ charge is located at one of the corners of the cube. What is the electric flux through the cube due to the $+Q$ charge?

Similar Questions

Electric field lines of force of a positive point charge are

The given figure shows the electric field lines due to two charges $q_1$ and $q_2$. What are the signs of the two charges?

An electric field,$\overrightarrow{E} = \frac{2 \hat{i} + 6 \hat{j} + 8 \hat{k}}{\sqrt{6}} \ V/m$,passes through a surface of $4 \ m^2$ area having a unit normal vector $\hat{n} = \left( \frac{2 \hat{i} + \hat{j} + \hat{k}}{\sqrt{6}} \right)$. The electric flux through that surface is:

The $S.I.$ unit of electric flux is

Two point charges $2q$ and $q$ are placed at vertex $A$ and the centre of face $CDEF$ of the cube,respectively,as shown in the figure. The electric flux passing through the cube is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module