In the figure,angle X = 62^o and angle XYZ = | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In $\Delta XYZ$,the sum of angles is $180^o$.$\angle XYZ + \angle YZX + \angle ZXY = 180^o$Given $\angle XYZ = 54^o$ and $\angle ZXY = 62^o$.$54^o

Vedclass · Accepted Answer

$32^o$ and $121^o$

Vedclass · Answer

(B) In $\Delta XYZ$,the sum of angles is $180^o$.$\angle XYZ + \angle YZX + \angle ZXY = 180^o$Given $\angle XYZ = 54^o$ and $\angle ZXY = 62^o$.$54^o + \angle YZX + 62^o = 180^o$$\angle YZX = 180^o - 116^o = 64^o$.Since $YO$ and $ZO$ are bisectors of $\angle XYZ$ and $\angle XZY$ respectively:$\angle OZY = \frac{1}{2} \angle XZY = \frac{1}{2} (64^o) = 32^o$.$\angle OYZ = \frac{1}{2} \angle XYZ = \frac{1}{2} (54^o) = 27^o$.In $\Delta OYZ$,the sum of angles is $180^o$:$\angle YOZ + \angle OYZ + \angle OZY = 180^o$$\angle YOZ + 27^o + 32^o = 180^o$$\angle YOZ = 180^o - 59^o = 121^o$.Thus,$\angle OZY = 32^o$ and $\angle YOZ = 121^o$.

In the figure,$\angle X = 62^o$ and $\angle XYZ = 54^o$. If $YO$ and $ZO$ are the bisectors of $\angle XYZ$ and $\angle XZY$ respectively of $\Delta XYZ$,find $\angle OZY$ and $\angle YOZ$.

Similar Questions

In the figure,$OP$,$OQ$,$OR$,and $OS$ are four rays. Prove that $\angle POQ + \angle QOR + \angle SOR + \angle POS = 360^o$.

In the figure,$POQ$ is a line. Ray $OR$ is perpendicular to line $PQ$. $OS$ is another ray lying between rays $OP$ and $OR$. Prove that $\angle ROS = \frac{1}{2}(\angle QOS - \angle POS)$.

In the figure,find the values of $x$ and $y$ and then show that $AB \parallel CD$.

In the figure,if $QT \perp PR$,$\angle TQR = 40^o$ and $\angle SPR = 30^o$,find $x$ and $y$.

In the figure,$AB \parallel CD$ and $CD \parallel EF$. Also,$EA \perp AB$. If $\angle BEF = 55^o$,find the values of $x, y$,and $z$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module