(A) For a parallel-plate capacitor,the charges on the facing surfaces are equal in magnitude and opposite in sign. Therefore,$Q_2 = -Q_3$.The potentia

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) For a parallel-plate capacitor,the charges on the facing surfaces are equal in magnitude and opposite in sign. Therefore,$Q_2 = -Q_3$.The potential difference $V$ between the plates is given by the charge on the inner surface divided by the capacitance $C$ of the capacitor.$V = \frac{Q_2}{C}$Since $Q_3 = -Q_2$,we can write $Q_2 = \frac{Q_2 - Q_3}{2}$.Substituting this into the potential difference formula:$V = \frac{Q_2 - Q_3}{2C}$

Class 12 Physics Electric Potential and Capacitance Parallel Plate Capacitor

Medium

In an insulated parallel-plate capacitor of capacitance $C$,the four surfaces have charges $Q_1, Q_2, Q_3$ and $Q_4$ as shown. The potential difference between the plates is

A
$\frac{Q_2 - Q_3}{2C}$
B
$\frac{Q_2 + 2Q_3}{2C}$
C
$\frac{Q_1 + Q_4}{2C}$
D
$\frac{Q_1 + Q_2 + Q_3 + Q_4}{2C}$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Physics Questions

Chapter

Electric Potential and Capacitance

Subtopic

Parallel Plate Capacitor

Two parallel plates separated by $d \ mm$ are kept at a potential difference of $V \ V$. $A$ particle of mass $m$ and charge $q$ enters the region between them with some velocity. The acceleration of the particle will be

MediumMHT CET 2022

View Solution

The following arrangement consists of five identical metal plates parallel to each other. The area of each plate is $A$ and the separation between successive plates is $d$. The capacitance between $P$ and $Q$ is

Medium

View Solution

In a parallel plate capacitor,if $10^{12}$ electrons pass from one plate to another,a potential difference of $10 \,V$ is developed across the plates. The capacitance of the capacitor is

MediumAP EAMCET 2022

View Solution

Charges of $2Q$ and $-Q$ are placed on two plates of a parallel plate capacitor. If the capacitance of the capacitor is $C$,find the potential difference between the plates.

Difficult

View Solution

Between the plates of a parallel plate capacitor,there is a $1\,mm$ thick paper of dielectric constant $4$. It is charged to $100\,V$. The electric field in $V/m$ between the plates of the capacitor is:

Easy

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

In an insulated parallel-plate capacitor of capacitance $C$,the four surfaces have charges $Q_1, Q_2, Q_3$ and $Q_4$ as shown. The potential difference between the plates is

Similar Questions

Two parallel plates separated by $d \ mm$ are kept at a potential difference of $V \ V$. $A$ particle of mass $m$ and charge $q$ enters the region between them with some velocity. The acceleration of the particle will be

The following arrangement consists of five identical metal plates parallel to each other. The area of each plate is $A$ and the separation between successive plates is $d$. The capacitance between $P$ and $Q$ is

In a parallel plate capacitor,if $10^{12}$ electrons pass from one plate to another,a potential difference of $10 \,V$ is developed across the plates. The capacitance of the capacitor is

Charges of $2Q$ and $-Q$ are placed on two plates of a parallel plate capacitor. If the capacitance of the capacitor is $C$,find the potential difference between the plates.

Between the plates of a parallel plate capacitor,there is a $1\,mm$ thick paper of dielectric constant $4$. It is charged to $100\,V$. The electric field in $V/m$ between the plates of the capacitor is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module