Charge of $2Q$ and $-Q$ are placed on two plates of a parallel plate capacitor if capacitance of capacitor is $C$ find potential difference between the plates
$V = \frac{Q}{C}$
$V = \frac{3Q}{2C}$
$V = \frac{2Q}{3C}$
None of these
A charge $q$ is placed at the centre of the line joining two equal charges $Q$. The system of the three charges will be in equilibrium, if $q$ is equal to
A parallel plate capacitor is charged to a potential difference of $100\,V$ and disconnected from the source of $emf$. A slab of dielectric is then inserted between the plates. Which of the following three quantities change?
$(i)$ The potential difference $(ii)$ The capacitance $(iii)$ The charge on the plates
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