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(B) The electric field $E$ between the plates of a capacitor is given by the formula $E = \frac{V}{d}$,where $V$ is the potential difference and $d$ i

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$100,000$

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(B) The electric field $E$ between the plates of a capacitor is given by the formula $E = \frac{V}{d}$,where $V$ is the potential difference and $d$ is the distance between the plates.Given:Potential difference $V = 100\,V$Distance $d = 1\,mm = 1 	imes 10^{-3}\,m$Substituting the values:$E = \frac{100}{1 	imes 10^{-3}} = 100 	imes 10^3 = 100,000\,V/m$.Note: The dielectric constant does not affect the electric field calculation when the potential difference $V$ is maintained constant across the plates.

Between the plates of a parallel plate capacitor,there is a $1\,mm$ thick paper of dielectric constant $4$. It is charged to $100\,V$. The electric field in $V/m$ between the plates of the capacitor is:

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