In an $ac$ circuit, the instantaneous voltage $e(t)$ and current $I(t)$ are given by $e(t)$ = $5[cos\ \omega t + \sqrt 3\ sin\ \omega t]\ volt$ $i (t)$ = $5[sin(\omega t +\frac {\pi}{4})]\ amp$ then
In an $ac$ circuit, the instantaneous voltage $e(t)$ and current $I(t)$ are given by $e(t)$ = $5[cos\ \omega t + \sqrt 3\ sin\ \omega t]\ volt$ $i (t)$ = $5[sin(\omega t +\frac {\pi}{4})]\ amp$ then
- A
Current leads voltage by $\frac {\pi}{4}$
- B
Voltage leads current by $\frac {\pi}{3}$
- C
Voltage leads current by $\frac {\pi}{6}$
- D
Current leads voltage by $\frac {\pi}{12}$
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