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Question

(C) The given equation for alternating voltage is $E = 141 \sin(628 t)$.Comparing this with the standard form $E = E_0 \sin(\omega t)$,we get the peak

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$100 	ext{ V}, 100 	ext{ Hz}$

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(C) The given equation for alternating voltage is $E = 141 \sin(628 t)$.Comparing this with the standard form $E = E_0 \sin(\omega t)$,we get the peak voltage $E_0 = 141 	ext{ V}$ and angular frequency $\omega = 628 	ext{ rad/s}$.The root mean square (rms) voltage is given by $E_{rms} = \frac{E_0}{\sqrt{2}} = \frac{141}{1.414} \approx 100 	ext{ V}$.The angular frequency is related to frequency $f$ by the formula $\omega = 2 \pi f$.Substituting the values,$628 = 2 	imes 3.14 	imes f$.$f = \frac{628}{6.28} = 100 	ext{ Hz}$.Thus,the rms voltage is $100 	ext{ V}$ and the frequency is $100 	ext{ Hz}$.

If an alternating voltage is represented as $E = 141 \sin(628 t)$,then the rms value of the voltage and the frequency are respectively:

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