$(a)$ The peak voltage of an $ac$ supply is $300\; V$. What is the $rms$ voltage?
$(b)$ The $rms$ value of current in an ac circuit is $10\; A$. What is the peak current?
$(a)$ Peak voltage of the ac supply, $V _{0}=300 \,V$ We know
$V_{m x}=\frac{V_{0}}{\sqrt{2}}=\frac{300}{\sqrt{2}}=212.1\, V$
$(b)$ The $rms$ value of current is given as $ I=10\,A$ Using above identity for current peak current is given as:
$I _{0}=1.414 \times I _{ rms }$
$I _{0}=1.414 \times 10=14.14 \,A$
The current flowing through an ac circuit is given by
$I=5 \sin (120 \pi t) A$
How long will the current take to reach the peak value starting from zero?
In general in an alternating current circuit
the reason why do we preferred an $a.c.$ voltage instead of $d.c.$ voltage.
The maximum value of $a.c.$ voltage in a circuit is $707V$. Its rms value is.....$V$
An alternating voltage is given by : $e = e_1\, \sin \omega t + e_2\, \cos \omega t$. Then the root mean square value of voltage is given by :-