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(B) The fringe width $\beta$ in a Young's double slit experiment is given by the formula $\beta = \frac{\lambda D}{d}$,where $\lambda$ is the waveleng

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(B) The fringe width $\beta$ in a Young's double slit experiment is given by the formula $\beta = \frac{\lambda D}{d}$,where $\lambda$ is the wavelength of light,$D$ is the distance between the slits and the screen,and $d$ is the distance between the two slits.From the formula,it is clear that $\beta \propto \lambda$.The wavelength of violet light $(\lambda_{violet})$ is shorter than the wavelength of blue light $(\lambda_{blue})$.Since the wavelength decreases when changing the source from blue to violet,the fringe width $\beta$ will also decrease.

In a Young's double slit experiment,the source illuminating the slits is changed from blue to violet. The width of the fringes

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